What is the maximum standard size rating of the motor branch-circuit short-circuit and ground-fault protective device for a 5-horsepower, 208-volt, 3-phase motor using time-delay fuses when starting current is not an issue?

Prepare for the Code Standards and Practices Level 6 Test. Use flashcards, multiple choice questions, and detailed explanations. Enhance your coding proficiency and get set for your exam!

Multiple Choice

What is the maximum standard size rating of the motor branch-circuit short-circuit and ground-fault protective device for a 5-horsepower, 208-volt, 3-phase motor using time-delay fuses when starting current is not an issue?

Explanation:
The main idea is how to size motor branch-circuit protection when using time-delay fuses and the starting surge isn’t a concern. For motors, the protection is tied to the full-load current, with NEC guidance allowing the protective device rating to be higher than the motor’s running current to accommodate inrush, but still within a defined upper limit. First estimate the motor’s full-load current. A 5-horsepower, 208-volt three-phase motor has a full-load current around 14 A (rough calculation: I_FL ≈ HP × 746 / (√3 × V × η × PF); using η ≈ 0.9 and PF ≈ 0.8 gives about 14 A). With time-delay fuses, you can size the protection up to about 2.5 times the full-load current when starting current isn’t an issue. That gives an upper limit of roughly 2.5 × 14 A ≈ 35 A. Standard fuse sizes available are typically 15, 20, 25, 30, 35, 40 A, etc. The largest standard size that stays within the 35 A limit is 30 A (in many standard sets, 35 A may or may not be used, but the common practical choice here is 30 A). So, the maximum standard size rating you’d use for this motor with time-delay fuses and no starting-current constraint is about 30 A.

The main idea is how to size motor branch-circuit protection when using time-delay fuses and the starting surge isn’t a concern. For motors, the protection is tied to the full-load current, with NEC guidance allowing the protective device rating to be higher than the motor’s running current to accommodate inrush, but still within a defined upper limit.

First estimate the motor’s full-load current. A 5-horsepower, 208-volt three-phase motor has a full-load current around 14 A (rough calculation: I_FL ≈ HP × 746 / (√3 × V × η × PF); using η ≈ 0.9 and PF ≈ 0.8 gives about 14 A).

With time-delay fuses, you can size the protection up to about 2.5 times the full-load current when starting current isn’t an issue. That gives an upper limit of roughly 2.5 × 14 A ≈ 35 A.

Standard fuse sizes available are typically 15, 20, 25, 30, 35, 40 A, etc. The largest standard size that stays within the 35 A limit is 30 A (in many standard sets, 35 A may or may not be used, but the common practical choice here is 30 A).

So, the maximum standard size rating you’d use for this motor with time-delay fuses and no starting-current constraint is about 30 A.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy